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25x^2-10x-624=0
a = 25; b = -10; c = -624;
Δ = b2-4ac
Δ = -102-4·25·(-624)
Δ = 62500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{62500}=250$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-250}{2*25}=\frac{-240}{50} =-4+4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+250}{2*25}=\frac{260}{50} =5+1/5 $
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